Warning: strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /home/question/public_html/scripts.php on line 1574
Warning: strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /home/question/public_html/scripts.php on line 1574
Q: ZOMG Help!!!111one
Submitted By: anon, 310 days, , 32 minutes ago
At 8pm a freight train leaves town traveling at 200 km/hr. At 1am a passenger train leaves the same station traveling in the same direction, along the same route at 130 mph. How long will it take the passenger train to overtake the freight train? How far will they be from the station at this time?
Please try not to post duplicate answers... if you see an answer that you want to post, just add a vote to it and you can add a note as well. Thank You
1
0
here's your bloody answer
Submitted By: michaeljh ( 308 days, 5 hours, 7 minutes ago )
Dude, it's not that hard, it's simple Algebra
rate * times = distance
rate(freight) * time(freight) = rate(passenger) * time(passenger)
Let x = time it takes for the trains to meet starting when the freight train started
200 * x = 209.21472 * (x - 5)
200x = 209.21472x - 046.0736
9.21472x = 1046.0736
x = 113.522017
It will take about 113 and a half hours for the passenger to overtake the freight.
They will be about 22704 km away from the station